Evaluate the function for the indicated values of x. function f(−10) = f(2) = f(−5) = f(−1) = f(8) =

f(−10) To find f(-10) we choose a function that has x value -10-10 <= -5 so we use f(x) = 2x + 1Plug in -10 for xf(-10) = 2(-10) +1 = -20 +1 = -19 So f(-10) = -19Now find f(2)2 lies between -5 and 5 so we use f(x) = x^2f(x) [tex] = x^2 [/tex]f(2) [tex] = 2^2 [/tex] = 4 . so f(2) = 4 f(−5) -5 is equal to -5 so we use f(x) = 2x + 1 f(-5) = 2(-5) + 1 = -10 + 1 = -9So f(-5) = -9 f(−1) -1 lies between -5 and 5 so we use f(x)= [tex] x^2 [/tex]f(-1)= [tex] (-1)^2 [/tex] = 1 so f(-1) = 1 f(8) 8 is greater than 5 so we use f(x) = 3 - xf(8) = 3 - 8 = -5 so f(8) = -5