Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula mc024-1.jpg, mc024-2.jpg with d being the distance they can see in miles and h being their eye-level height in feet.
Accepted Solution
A:
The formula is:
d = √ [ 3h / 2], for h > 0
where d is the distance they can see in miles, and h is their eye-level height in feet.
In the case of Wyatt, h = 120 ft
=> d = √ [ 3(120) ] / 2 = √180 = 13.42 miles
In the case of Shawn, h = 270 ft
=> d = √ [ 3 (270) / 2 ] = √ 405 = 20.12 miles
Given that the question is how much farther Shawn can see to the horizon, you must find the difference: