Here are two closed containers and four balls just fit into each container. Each ball has a diameter of 60mm. Which container has the smaller surface area? You must show your working. Mathswatch

Answer:"A is smaller"Step-by-step explanation:The full question is attached.Surface area of cylinder:The formula is  [tex]SA=2\pi r^2 + 2\pi r h[/tex]where r is the radius and h is the heightHere, radius would be 30 since balls have diameter 60 and radius is half of that.Also height is the diameter of 4 balls line-by-line, so height is 60*4 = 240Now, plugging into the formula, we get:[tex]SA=2\pi r^2 + 2\pi r h\\SA=2\pi (30)^2 + 2\pi (30) (240)\\SA=50,868[/tex]Surface Area of rectangular prism:The surface area of rectangular prism is the area of all the rectangular surfaces (6 of them).Area of top and bottom = (60+60)*(60+60) * 2 = 120*120 * 2 = 28,800Area of 2 sides = 2 * (60*120) = 14,400Area of front and back = 2 * (60*120) = 14,400Total Surface Area = 28,800 + 14,400 + 14,400 = 57,600Thus, cylinder has smaller surface area."A is smaller"